If the reaction of 20.7 grams of CaCO3 produces 6.81 grams of CaO, what is the percent yield? CaCO3=>CaO+CO2

Answer 1

CaC#O_3# --------> CaO + C#O_2#

20.7 g 6.81g +

In any chemical reaction, the total mass of the reactants and products is equal, according to the law of conservation of mass.

mass of C#O_2# + mass of CaO is equal to the mass of CaC#O_3# .

mass of C#O_2# + 6.81g = 20.7g

mass of C#O_2# = 20.7g- 6.81g = 13.89g

Mass of product Z x 100 / mass of reactant equals the percentage yield of a product Z.

% yield of Product C#O_2# = 13.89 x 100 / 20.7 = 67. 10%

Product CaO yield percentage = 6.81g x 100 /20.7 = 32.89%

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Answer 2

Owen Ambrose

Percent yield = (Actual yield / Theoretical yield) * 100

The molar mass of CaCO3 is 100.09 g/mol. The molar mass of CaO is 56.08 g/mol.

Theoretical yield of CaO = (20.7 g / 100.09 g/mol) * 56.08 g/mol = 11.59 g

Percent yield = (6.81 g / 11.59 g) * 100 ≈ 58.82%

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

If the reaction of 20.7 grams of CaCO3 produces 6.81 grams of CaO, what is the percent yield? CaCO3=&gt;CaO+CO2

If the reaction of 20.7 grams of CaCO3 produces 6.81 grams of CaO, what is the percent yield? CaCO3=>CaO+CO2