If the length of a #47# #cm# spring increases to #89# #cm# when a #2# #kg# weight is hanging from it, what is the spring's constant?
We should work in SI units, so the stretch is
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To find the spring constant (k), you can use Hooke's Law: F = kx, where F is the force applied, k is the spring constant, and x is the displacement from the equilibrium position.
First, calculate the force applied using the weight and gravity: F = mg, where m is the mass (2 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Then, calculate the displacement (x) of the spring: x = (final length - initial length) = (89 cm - 47 cm).
Once you have the force and displacement, you can solve for the spring constant (k) using Hooke's Law: k = F / x.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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