# If the length of a #13 cm# spring increases to #45 cm# when a #4 kg# weight is hanging from it, what is the spring's constant?

Using Hooke's law, we can say that

where

Thus, the constant of the spring is:

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To find the spring constant (k), you can use Hooke's Law equation: ( F = kx ), where ( F ) is the force applied to the spring, ( k ) is the spring constant, and ( x ) is the displacement from the equilibrium position. Rearranging the equation to solve for ( k ), we have: ( k = \frac{F}{x} ). Given that the weight (force) applied is 4 kg (which can be converted to Newtons) and the displacement is the change in length from 13 cm to 45 cm, you can calculate the spring constant.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- An object with a mass of #5 kg# is on a plane with an incline of # -(5 pi)/12 #. If it takes #12 N# to start pushing the object down the plane and #2 N# to keep pushing it, what are the coefficients of static and kinetic friction?
- If the length of a #65 cm# spring increases to #94 cm# when a #5 kg# weight is hanging from it, what is the spring's constant?
- How can I calculate the Newton's second law?

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