If the frequency of the #p# allele is .63 in the population then what is the frequency of the #q# allele?

Answer 1

#0.37#

The Hardy-Weinberg equation, which we employ, says that,

#p^2+2pq+q^2=1#

where

#p^2 #is the frequency of the homozygous genotype #"AA"#
#2pq# is the frequency of the heterozygous genotype #"Aa"#
#q^2# is the frequency of the homozygous genotype #"aa"#
#p# is the frequency of the dominant allele #"A"#
#q# is the frequency of the recessive allele #"a"#
Since we only need to find the frequency of the #q# allele, we can factor the equation into:
#(p+q)^2=1#
Plugging in for #p=0.63#, we get:
#(0.63+q)^2=1#
#0.63+q=1#
#q=1-0.63#
#=0.37#
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Answer 2

The frequency of the q allele would be 1 - p, so if the frequency of the p allele is 0.63, then the frequency of the q allele would be 1 - 0.63 = 0.37.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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