If the earth was reduced to the size of an atom how big would the galaxy be?

Answer 1

#x=((1xx10^(-10))(1xx10^21))/12742000=(1xx10^11)/12742000~=7848m~~8km#

We have a ratio question - given the size of the Earth and reducing it to the size of an atom, how big will the galaxy be? That looks like:

#"Earth"/"atom"="galaxy"/x#

So first off we can solve for x:

#x=("atom"xx"galaxy")/"Earth"#
And now we need to make a decision - the size of an atom depends on which atom we're talking about. They typically run between #0.1 to 0.5# nanometres. I'm going to assume we're using a smaller atom (it'll make the math easier).

And now let's get some numbers:

#"Earth"=12,742 km=12,742,000 m#
#"Atom"= 1 xx 10^-10 m#
#"Galaxy" = 1,000,000,000,000,000,000,000=1xx10^21m#

And now the math:

#x=((1xx10^(-10))(1xx10^21))/12742000=(1xx10^11)/12742000~=7848m~~8km#
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Answer 2

The Milky Way galaxy would remain roughly the same size if Earth were shrunk to the size of an atom because an atom is incredibly small in comparison to a galaxy's enormous scale.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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