If the diameter of a sphere is 10, what is the approximate volume of the sphere?

Answer 1

#V~~523.61#

The volume of a sphere can be calculated with this formula:

#V=4/3pir^3# where #r# is the radius (half the diameter).
Since the diameter is 10, the radius is #10-:2# or 5
#V=4/3pi5^3#
#V=4/3pi*125#
#V=4/3*125*pi#
#V=500/3*pi#
#V~~166.67*pi#
#V~~523.61#
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Answer 2

The approximate volume ( V ) of a sphere can be calculated using the formula:

[ V = \frac{4}{3} \pi r^3 ]

where ( r ) is the radius of the sphere.

Given that the diameter of the sphere is 10, the radius ( r ) is half of the diameter, so ( r = \frac{10}{2} = 5 ).

Substituting the value of the radius into the formula, we get:

[ V = \frac{4}{3} \pi (5)^3 ]

[ V = \frac{4}{3} \times \pi \times 125 ]

[ V \approx \frac{4}{3} \times 3.14159 \times 125 ]

[ V \approx 523.598 ]

So, the approximate volume of the sphere is ( 523.598 ) cubic units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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