If the burning of the fuel in a potato cannon performs 855 J of work on the potato and produces 1422 J of heat, what is #DeltaE# for the burning of the fuel?

Answer 1

#-"2277 J"#

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Answer 2

DeltaE = Q - W Where: DeltaE = change in internal energy Q = heat added to the system W = work done by the system

Given: Q = 1422 J (heat produced) W = 855 J (work done on the potato)

DeltaE = 1422 J - 855 J DeltaE = 567 J

Therefore, the change in internal energy for the burning of the fuel is 567 J.

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Answer 3

The change in internal energy (ΔE) for the burning of the fuel can be calculated using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔE = Q - W

Where: ΔE = change in internal energy Q = heat added to the system W = work done by the system

Given: Q = 1422 J (heat produced) W = 855 J (work done on the potato)

Plugging in the values:

ΔE = 1422 J - 855 J ΔE = 567 J

Therefore, the change in internal energy (ΔE) for the burning of the fuel is 567 Joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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