If #sinx=(4/5)#, how do you find #sin2x#?
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you prove that #(1 + tan theta)[1 + tan(1/4 pi - theta)] = 2#?
- How do you find the value of #cos((7pi)/8)# using the double or half angle formula?
- How do you solve (cscx-cotx)^4(cscx+cotx)^4=1?
- How to use the product-to-sum formula to write the product as a sum or difference? 4 cos pi/3 sin 5pi/6
- How do you simplify #Tan(x) Csc(x)/sec(x)#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7