If sides A and B of a triangle have lengths of 3 and 5 respectively, and the angle between them is #(pi)/3#, then what is the area of the triangle?
The area of the triangle is
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Using the formula for the area of a triangle, which is ( \frac{1}{2} \times \text{base} \times \text{height} ), and knowing that the height of the triangle is given by ( A \times \sin(\theta) ), where ( A ) is the length of side ( A ) and ( \theta ) is the angle between sides ( A ) and ( B ), we can calculate the area of the triangle. Therefore, the area of the triangle is ( \frac{1}{2} \times 5 \times 3 \times \sin\left(\frac{\pi}{3}\right) ). Evaluating this expression yields an area of ( \frac{15\sqrt{3}}{4} ) square units.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you determine whether #triangle ABC# has no, one, or two solutions given #A=44^circ, a=14, b=19#?
- If sides A and B of a triangle have lengths of 5 and 6 respectively, and the angle between them is #(pi)/2#, then what is the area of the triangle?

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