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If it takes an electric toy train 5 seconds to pull a coal car 1.5 m, and it exerts a constant force of 4 N during this time, what is its power?

Answer 1

William Audy

#1.2 " Watt"#

#Power=(fs)/(t)#

# =(4N*1.5 m)/(5s)#

#= (6Nm)/(5s)#

#= 1.2 " Watt"#

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Answer 2

Nicholas Agrusa

To find the power of the electric toy train, you can use the formula:

[ \text{Power} = \frac{\text{Work}}{\text{Time}} ]

Given that the train exerts a constant force of ( 4 , \text{N} ) to pull the coal car a distance of ( 1.5 , \text{m} ) in ( 5 , \text{seconds} ), you can calculate the work done by the train using the formula:

[ \text{Work} = \text{Force} \times \text{Distance} ]

Substituting the given values:

[ \text{Work} = 4 , \text{N} \times 1.5 , \text{m} ]

Now, calculate the work:

[ \text{Work} = 6 , \text{J} ]

Next, substitute the work and time into the power formula:

[ \text{Power} = \frac{6 , \text{J}}{5 , \text{s}} ]

[ \text{Power} = 1.2 , \text{W} ]

Therefore, the power of the electric toy train is ( 1.2 , \text{W} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.