If it takes 25 mL of 0.05 M #HCl# to neutralize 345 mL of #NaOH# solution, what is the concentration of the #NaOH# solution?

Answer 1

#[NaOH]~=4xx10^-3*mol*L^-1#

#NaOH(aq) + HCl(aq) rarr NaCl(aq) + H_2O(l)#

The ratio of acid to base is one to one.

Thus #[NaOH]# #=# #(25xx10^-3Lxx0.05*mol*L^-1)/(345xx10^-3L)#
#=# #??*mol*L^-1#
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Answer 2

The concentration of the NaOH solution is 0.00363 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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