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If #h(x) = -x^2 - 3x#, how do you solve h(-4)?

Answer 1

Ethan Adkins

To solve h(-4), substitute -4 for x in the function h(x) = -x^2 - 3x.

h(-4) = -(-4)^2 - 3(-4)
h(-4) = -16 + 12
h(-4) = -4

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Answer 2

Eli Assouline

h(-4) = -4

Since x is given (x = -4). Then, all you need to do is log in -4 for each value of x h(-4) = #-(-4)^2# -3(-4) h(-4) = -(16) + 12 = -4

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Answer 3

Avery Alexander

#h(-4)=-4#

#h(x)=-x^2-3x#

#h(-4)=-(-4)^2-3(-4)#

#h(-4)=-16-(-12))#

#h(-4)=-16+12#

#h(-4)=-4#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.