If #h(x)=(f+g)(x), f(x)=5x+2# how do you determine g(x) given #h(x)=sqrt(x+7)+5x+2#?
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To determine ( g(x) ) given ( h(x) = \sqrt{x + 7} + 5x + 2 ) and ( f(x) = 5x + 2 ), subtract ( f(x) ) from ( h(x) ) to find ( g(x) ):
[ g(x) = h(x) - f(x) ]
[ g(x) = (\sqrt{x + 7} + 5x + 2) - (5x + 2) ]
[ g(x) = \sqrt{x + 7} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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