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If #g(x) = 2x-5#, how do you find g(x)=1/3?

Answer 1

Jameson Allen

To find when ( g(x) = \frac{1}{3} ), set ( g(x) = \frac{1}{3} ) and solve for ( x ):

[ 2x - 5 = \frac{1}{3} ]

[ 2x = \frac{1}{3} + 5 ]

[ 2x = \frac{16}{3} ]

[ x = \frac{16}{6} ]

[ x = \frac{8}{3} ]

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Answer 2

Avery Alexander

Possibility 1 You want to find the value of #x# for which #g(x) = 1/3# given #g(x) = 2x-5# #color(white)("XXXX")##2x-5 = 1/3# #color(white)("XXXX")##6x-15 = 1# #color(white)("XXXX")#x = 16/6 = 8/3#

Possibility 2 You want to find the value of #g(x)# when #x=1/3# #color(white)("XXXX")##g(1/3) = 2(1/3)-5# #color(white)("XXXX")##color(white)("XXXX")##= 2/3 -5# #color(white)("XXXX")##color(white)("XXXX")##=- 4 1/3#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.