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If #f(x) = x^2-1# and #g(x)=1-x#, how do you find f(g(x))?

Answer 1

Eva Adamson

Substitute (g(x)) into (f(x)):

[ f(g(x)) = f(1-x) ]

Replace (x) in (f(x)) with (1-x):

[ f(g(x)) = (1-x)^2 - 1 ]

Simplify the expression:

[ f(g(x)) = x^2 - 2x + 1 - 1 ]

Combine like terms:

[ f(g(x)) = x^2 - 2x ]

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Answer 2

Avery Alexander

You just substitute the #g(x)# function into the #f(x)#

#f(g(x))=f(1-x)# #=(1-x)^2-1# #=(1-2x+x^2)-1# #=x^2-2xorx(x-2)#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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