# If f(x) = 1/(x+1) and g(x) = 2/(2x-1) how do you find g(f(x)) and its domain and range?

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To find g(f(x)), first substitute f(x) into g(x), then determine the domain and range. So, g(f(x)) = 2 / (2 * (1 / (x + 1)) - 1). Simplifying this expression gives g(f(x)) = 2 / ((2 / (x + 1)) - 1), which further simplifies to g(f(x)) = 2 / ((2 - (x + 1)) / (x + 1)). Finally, g(f(x)) = 2 * (x + 1) / (2 - (x + 1)). The domain of g(f(x)) is all real numbers except x = -1, and the range is all real numbers except y = 2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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