If an object with uniform acceleration (or deceleration) has a speed of #1 m/s# at #t=0# and moves a total of 180 m by #t=4#, what was the object's rate of acceleration?

Answer 1

#22 " ms"^-2#

The average speed of the particle over 4 s is #{180 " m"}/{4 " s"} = 45 "m"/"s"#.

Since for a uniformly moving object the average speed over an interval is the average of the initial and final speeds, the final speed must be #= 2times 45 "m"/"s" - 1 "m"/"s" = 89 "m"/"s"#.

Thus, the acceleration is #(89 " ms"^-1 - 1" ms"^-1)/{4" s"}=22 " ms"^-2#

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Answer 2

Leo Abeyta

The object's rate of acceleration is (0.25 , \text{m/s}^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.