If an object is moving at #60 m/s# and accelerates to #145 m/s# over 5 seconds, what was the object's rate of acceleration?

Answer 1

The acceleration is #"17 m/s"^2"#.

Use the formula #a=(v_f-v_i)/(Delta t)#, where #a# is acceleration, #v_i# is initial velocity, #v_f# is final velocity, and #Delta t# is time interval.

Known #v_i="60 m/s"# #v_f="145 m/s"# #Delta t="5 s"#

Unknown #a#

Solution Substitute the known variables into the formula and solve.

#a=(v_f-v_i)/(Delta t)#

#a=(145"m/s"-60"m/s")/(5"s")#

#a=(85"m/s")/(5"s")#

#a="17 m/s"^2"#

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Answer 2

Layla Ahmed

The object's rate of acceleration was ( 17 , \text{m/s}^2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.