# If an object is moving at #18 m/s# over a surface with a kinetic friction coefficient of #u_k=12 /g#, how far will the object continue to move?

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To find the distance the object will continue to move, you can use the equation:

(d = \frac{v^2}{2 \mu_k g})

Where:

- (d) is the distance
- (v) is the initial velocity (18 m/s in this case)
- (\mu_k) is the kinetic friction coefficient (0.12 in this case)
- (g) is the acceleration due to gravity (approximately 9.8 m/s²)

Plugging in the values:

(d = \frac{(18 , \text{m/s})^2}{2 \times 0.12 \times 9.8 , \text{m/s}^2})

(d ≈ \frac{324}{23.52})

(d ≈ 13.78 , \text{meters})

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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