If an object is moving at #150 m/s# over a surface with a kinetic friction coefficient of #u_k=2250 /g#, how far will the object continue to move?

Answer 1

#Delta x=5 m#

#v_i=150 m/s" initial velocity"#
#u_k=2250/g" coefficient of friction"#

#"The object is decreased by the friction force"#

#F_f=u_k*m*g" #

#F_f=2250/cancel(g)*m*cancel(g)#

#F=m*a#

#2250*cancel(m)=cancel(m)*a#

#a=2250" " m/s^2#

#v_f^2=v_i^2-2*a*Delta x#

#"the final velocity of object will be zero if object stops." #

#0=v_i^2-2*a*Delta x#

#Delta x=v_i^2/(2*a)#

#Delta x=150^2/(2250)#

#Delta x=22500/(2*2250)#

#Delta x=5 m#

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Answer 2

Use the following equation to find the distance (d) the object will continue to move:

[ d = \frac{v^2}{2 \cdot g \cdot u_k} ]

Where: ( v = ) velocity of the object (150 m/s) ( g = ) acceleration due to gravity (approximately 9.8 m/s²) ( u_k = ) kinetic friction coefficient (2250 / g)

Substitute the values into the equation to find the distance.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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