If an object is dropped, how fast will it be moving after #12s#?

Answer 1

The answer is #117.6m/s#.

The standard formula for the final speed of an object that moves with constant acceleration (in this case #g#, the gravitational acceleration) is:

#v=v_0+g t#

As the initial velocity #v_0# is equal to #0# (as the object is initially at rest), we get (of course without taking air friction into account):

#v=9.8 m/s^2 \cdot 12s=117.6m/s#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Adam Arnold

The speed of an object dropped near the surface of the Earth increases at a rate of approximately 9.8 meters per second squared (m/s^2) due to gravity. After 12 seconds, neglecting air resistance, the object will be moving at a speed of approximately 117.6 meters per second.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.