# If an astronaut dropped a small rock near the surface of Mars, how far would the rock fall in 1.35 s?

Mars- Earth g-ratio is 0.38, nearly. Answer 11' 1", nearly.

Near Earth, the distance fallen through will be 29' 2", nearly.

The distance fallen in a drop is s = (g t^2) / 2, and the acceleration caused by Mars's gravity on its surface is approximately 0.38 X 32'/ s/s.= 12' 2" /s/s, approximately.

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The acceleration due to gravity on Mars is approximately 3.7 m/s². Using the equation for distance fallen: d = 0.5 * g * t^2, where d is the distance fallen, g is the acceleration due to gravity, and t is the time, we can calculate the distance fallen. Plugging in the values: d = 0.5 * 3.7 m/s² * (1.35 s)^2. Solving for d, the distance fallen is approximately 3.71 meters.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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