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If an angle is 18 degrees less than twice its complement, how do you find the ratio of the angle to its complement?

Answer 1

Let's call the angle we seek #alpha#

Then the complement is defined as #90^o-alpha# And twice the complement would then be: #2*(90^o-alpha)=180^o-2alpha#

So the equation turns into: #alpha=(180^o-2alpha)-18^o=162^o-2alpha-># Add #2alpha# to both sides, later divide by #3#: #3alpha=162^o->alpha=54^o#

Check your answer :

If #alpha=54^o->#complement=#36^o# Twice complement=#72^o# Difference=#18^o# Check!

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Answer 2

Eva Adamson

To find the ratio of the angle to its complement, we can set up an equation. Let's denote the angle as x and its complement as 90 - x. According to the given information, x = 2(90 - x) - 18. Simplifying this equation, we get x = 162 - 2x. Combining like terms, we have 3x = 162. Dividing both sides by 3, we find x = 54. Therefore, the angle is 54 degrees and its complement is 90 - 54 = 36 degrees. The ratio of the angle to its complement is 54/36, which simplifies to 3/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.