If a worker pulls a 10kg bucket up a 25 m well, how much work has he or she done?

Answer 1

#2450# joules

Work done #W#, when an object of mass #m# #kg# is raised to a height of #h# #m# is given by #W=mgh# joules, where #g# is acceleration due to gravity in #SI# units and is #9.8# #m/s^2#.

Hence, in the given case work done is

#10xx9.8xx25=2450# joules

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Carson Alexander

The work done by the worker is equal to the force applied multiplied by the distance moved in the direction of the force. In this case, the force is equal to the weight of the bucket, which is ( F = m \times g ), where ( m = 10 ) kg is the mass of the bucket and ( g = 9.8 ) m/s² is the acceleration due to gravity. So, ( F = 10 \times 9.8 = 98 ) N. The distance moved is ( d = 25 ) m. Therefore, the work done is ( W = F \times d = 98 \times 25 = 2450 ) joules.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.