If a spring has a constant of #9 (kg)/s^2#, how much work will it take to extend the spring by #22 cm #?
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To calculate the work required to extend the spring by 22 cm, we use the formula:
[ \text{Work} = \frac{1}{2}kx^2 ]
where ( k ) is the spring constant and ( x ) is the displacement from the equilibrium position.
First, we convert 22 cm to meters: ( 22 , \text{cm} = 0.22 , \text{m} ).
Then, we plug in the values:
[ \text{Work} = \frac{1}{2} \times 9 , \text{(kg/s}^2) \times (0.22 , \text{m})^2 ]
[ \text{Work} = \frac{1}{2} \times 9 \times 0.0484 ]
[ \text{Work} = 2.178 , \text{J} ]
So, it will take 2.178 J of work to extend the spring by 22 cm.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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