# If a spring has a constant of #6 (kg)/s^2#, how much work will it take to compress the spring #7 cm #?

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To calculate the work done to compress a spring, you can use the formula: ( W = \frac{1}{2}kx^2 ), where ( k ) is the spring constant and ( x ) is the displacement from the equilibrium position. Given that the spring constant ( k = 6 , \text{(kg/s)}^2 ) and the displacement ( x = 7 , \text{cm} = 0.07 , \text{m} ), the work done is ( W = \frac{1}{2} \times 6 \times (0.07)^2 = 0.0147 , \text{J} ). Therefore, it will take approximately 0.0147 Joules of work to compress the spring 7 cm.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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