If a spring has a constant of #4 (kg)/s^2#, how much work will it take to extend the spring by #78 cm #?

Answer 1

Work done in extending a spring ,is stored in it as elastic potential energy,and that is expressed as #1/2 kx^2#(where, #k# is the spring constant and #x# is the amount by which it is extended)

Given, #k=4 , x=78/100#

So, work done = #1/2 *4 (78/100)^2=1.217 J#

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Answer 2

Layla Ahmed

To calculate the work done to extend the spring by 78 cm, you can use the formula for the work done by a spring, which is ( W = \frac{1}{2} k x^2 ), where ( k ) is the spring constant and ( x ) is the displacement from the equilibrium position.

First, convert the displacement from centimeters to meters: ( x = 78 , \text{cm} = 0.78 , \text{m} )

Now, plug in the values into the formula: ( W = \frac{1}{2} (4 , \text{kg/s}^2) (0.78 , \text{m})^2 )

( W = \frac{1}{2} (4) (0.6084) )

( W = 1.2168 , \text{J} )

So, it will take approximately 1.2168 joules of work to extend the spring by 78 cm.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.