# If a spring has a constant of #4 (kg)/s^2#, how much work will it take to extend the spring by #65 cm #?

The work done is

We employ the spring's work equation, which says that,

Take note of this:

Thus, we have:

Thus, the completed work is:

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To calculate the work done to extend the spring, you can use the formula:

[ W = \frac{1}{2} k x^2 ]

Where:

- ( W ) is the work done,
- ( k ) is the spring constant (4 kg/s² in this case),
- ( x ) is the displacement from the equilibrium position (0.65 m in this case).

[ W = \frac{1}{2} \times 4 \times (0.65)^2 = 0.845 , \text{J} ]

So, it will take approximately 0.845 joules of work to extend the spring by 65 cm.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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