# If a spring has a constant of #2 (kg)/s^2#, how much work will it take to extend the spring by #56 cm #?

Around

On a spring, work is provided by:

where:

So, the completed work is:

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To calculate the work done to extend the spring, we use the formula:

Work = (1/2) * k * (extension)^2

where k is the spring constant and extension is the change in length of the spring.

Given that the spring constant (k) is 2 (kg)/s^2 and the extension is 56 cm (or 0.56 m), we plug these values into the formula:

Work = (1/2) * 2 * (0.56)^2 = 0.5 * 2 * 0.3136 = 0.6268 J

Therefore, it will take approximately 0.6268 joules of work to extend the spring by 56 cm.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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