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If a spring has a constant of #10 (kg)/s^2#, how much work will it take to extend the spring by #40cm #?

Answer 1

I found: #0.8J#

The work needed to extend the spring will be equal to the final Elastic Potential Energy gained by the system because of the extension, i.e.: #W=1/2kx^2=1/2*10*(0.4)^2=0.8J#
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Answer 2

The work done to extend the spring by 40 cm is 4 J.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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