If a solution contains 3.458 moles of #CuCl_2# in 1.500 L, what is the solution's molarity?

Answer 1

Molarity is equal to total moles divided by total liters ...

Molarity #=3.458/1.500=2.305# M

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Answer 2

The molarity of a solution is calculated using the formula:

Molarity (M) = moles of solute / liters of solution

Given:

  • Moles of CuCl₂ = 3.458 moles
  • Volume of solution = 1.500 L

Using the formula:

Molarity (M) = 3.458 moles / 1.500 L ≈ 2.305 M

Therefore, the molarity of the solution containing 3.458 moles of CuCl₂ in 1.500 L is approximately 2.305 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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