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If a rocket with a mass of 4000 tons vertically accelerates at a rate of # 9/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 11 seconds?

Answer 1

Amelia Adams

#P=8,74*10^9W=8,74GW#

The power at a single moment is given by the formula :

#P=vF#

Let's find the force first :

#ΣF=ma=>F-mg=ma=>F=m(g+a)=#

#4*10^6(9,81+4,5)=176,6*10^6=1.766*10^8N#

Now let's find the velocity :

#v=at=4,5*11=49,5m/s#

The power is therefore :

#P=vF=49,5*1,766*10^8=87,4*10^8=8,74*10^9W=#

#8,74GW#

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Answer 2

Olivia Askew

Power = Force × Velocity Force = Mass × Acceleration

Power = (4000 tons × 9.8 m/s²) × (9/5 m/s²) × 11 seconds

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.