# If a rocket with a mass of 3500 tons vertically accelerates at a rate of # 3/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 12 seconds?

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To calculate the power the rocket must exert to maintain its acceleration, we can use the formula for power:

[ \text{Power} = \text{Force} \times \text{Velocity} ]

The force required to maintain the acceleration can be calculated using Newton's second law of motion:

[ \text{Force} = \text{Mass} \times \text{Acceleration} ]

Given that the mass of the rocket is 3500 tons (which is 3,500,000 kg), and the acceleration is ( \frac{3}{5} ) m/s², we can calculate the force:

[ \text{Force} = 3,500,000 \times \frac{3}{5} ]

Now, we need to find the velocity of the rocket at 12 seconds. Assuming it starts from rest, the velocity can be calculated using the formula:

[ \text{Velocity} = \text{Acceleration} \times \text{Time} ]

[ \text{Velocity} = \frac{3}{5} \times 12 ]

Now, we can calculate the power:

[ \text{Power} = \text{Force} \times \text{Velocity} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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