If a riding mower costs $300 more than a self-propelled mower and the combined cost of the two mowers is $1100, what is the cost of each mower?

Question

Avery Alexander · Accepted Answer

The riding mower is $700 and the self-propelled mower is $400.

Because the riding mower is $300 more, the x in your equation will be the cost of the self-propelled mower. riding mower= x+300 self-propelled mower= x total cost= 1100 The equation is then built as the following based on the above. 1100=x+(x+300) There are no coefficients involved based on the given information that there are only two mowers. Then we solve: 1100=2x+300 1100-300=2+300-300 800=2x Divide both sides by 2 400=x So, the riding mower is $700 and the self-propelled mower is $400.

Eva Abramson · Answer

The self-propelled mower costs #$400#, and the riding mower costs #$700#.

Let #x# equal the cost of the self-propelled mower, and #(x+$300)# equal the cost of the riding mower. #x+(x+$300)=$1100# Simplify. #2x+$300=$1100# Subtract #$300# from both sides. #2x=$1100-300# #2x=$800# Divide both sides by #2#. #x=$400# #x+$300=$400+$300=$700# The self-propelled mower costs #$400#, and the riding mower costs #$700#.

Eva Abramson · Answer

undefined Let x be the cost of the self-propelled mower.
Then, the cost of the riding mower is x + $300.
The total cost of the two mowers is $1100.
So, x + (x + $300) = $1100.
Solve for x to find the cost of the self-propelled mower.
Then, add $300 to find the cost of the riding mower.