If a rectangle measures 8 feet on the short side and 9.8 feet on the long side.What is the area of the rectangle in square feet?

Question

Aurora Ayala · Accepted Answer

#A=78.4# #"ft"^2# Multiply the length and width of the rectangle to find its area: #A=9.8*8# #A=78.4# #"ft"^2# Remember your units!

Sadie Adams · Answer

If the decimal is giving you a problem consider this approach.

#78.4 color(white)(.)ft^2# We have: #8" feet"xx9.8" feet"# But 9.8 is the same as #98xx1/10# So re-write as: #8xx98xx1/10 " ft"^2# #color(white)("d")color(white)(.)9color(white)(..)8# #ul(color(white)("d")color(white)(9999)8larr" Multiply")# #ul(7color(white)(.)8color(white)(..)4)# #color(white)("dd")6# Now we multiply by #1/10# to give: #784 color(white)(.)ft^2xx1/10= 78.4 color(white)(.)ft^2#

Aurora Ayala · Answer

undefined The area of a rectangle is calculated by multiplying its length by its width. In this case, the short side measures 8 feet and the long side measures 9.8 feet.

$$ \text{Area} = \text{Length} \times \text{Width} $$

$$ \text{Area} = 8 \text{ feet} \times 9.8 \text{ feet} $$

$$ \text{Area} = 78.4 \text{ square feet} $$

So, the area of the rectangle is $ 78.4 $ square feet.