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If a projectile is shot at an angle of #pi/2# and at a velocity of #31 m/s#, when will it reach its maximum height??

Answer 1

Charlotte Aaron

#"3.2 s"#

The time needed to reach the highest point is provided by

#"T" = "usinθ"/"g"#

#color(white)("T") = "31 m/s × sin(π/2)"/"9.8 m/s"^2#

#color(white)("T") = 3.2\ "s"#

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Answer 2

Layla Ahmed

The projectile will reach its maximum height when its vertical component of velocity becomes zero. In this case, the time of flight to reach maximum height can be calculated using the formula: ( t = \frac{v_0 \sin(\theta)}{g} ), where ( v_0 ) is the initial velocity, ( \theta ) is the launch angle, and ( g ) is the acceleration due to gravity. Plug in the values to find the time.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.