If a projectile is shot at an angle of #pi/2# and at a velocity of #22 m/s#, when will it reach its maximum height??

Answer 1

I got: #2.2s#

If I interpreted it right, the bullet is shot perfectly vertically and will reach its maximum height where its final velocity #v_f# will be zero. We can use kinematics in the form of the relationship: #v_f=v_i+at# where the acceleration #a# will be acceleration of gravity #g=9.8m/s^2# directed downwards (and so it will have a negative sign). We get: #0=22-9.8t# rearranging: #t=22/9.8=2.2s#
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Answer 2

The projectile will reach its maximum height immediately after being launched.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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