If a projectile is shot at an angle of #(2pi)/3# and at a velocity of #6 m/s#, when will it reach its maximum height?

Answer 1

The projectile will reach its maximum height at 0.53 s

We consider the equation #s=vt-1/2at^2# and #v=v-at# we find the moment when the horizontal component of speed is 0 (the vertical component is v(x)=vsin(a)) so we have the equation #v-at=0# a is equal to g, so #t=v/g=0.53 m/s^2#
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Answer 2

The projectile will reach its maximum height halfway through its total flight time.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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