# If a gas at occupies 2.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 3.50 atm?

Approx.

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Using Boyle's Law, (P_1V_1 = P_2V_2), where (P_1) and (V_1) are the initial pressure and volume, and (P_2) and (V_2) are the final pressure and volume, respectively, we can solve for (V_2):

(P_1V_1 = P_2V_2)

(1.00 , \text{atm} \times 2.60 , \text{L} = 3.50 , \text{atm} \times V_2)

(V_2 = \frac{1.00 , \text{atm} \times 2.60 , \text{L}}{3.50 , \text{atm}})

(V_2 = 0.743 , \text{L})

Therefore, the volume of the gas at a pressure of 3.50 atm would be approximately 0.743 liters.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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