# If a current of #8 A# passing through a circuit generates #16 W# of power, what is the resistance of the circuit?

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To find the resistance of the circuit, we can use Ohm's Law, which states:

[ P = I^2 \cdot R ]

where:

- ( P ) is the power (in watts),
- ( I ) is the current (in amperes),
- ( R ) is the resistance (in ohms).

Given:

- ( P = 16 , \text{W} ) (power)
- ( I = 8 , \text{A} ) (current)

Rearrange the formula to solve for resistance:

[ R = \frac{P}{I^2} ]

Substitute the given values:

[ R = \frac{16 , \text{W}}{(8 , \text{A})^2} ]

[ R = \frac{16 , \text{W}}{64 , \text{A}^2} ]

[ R = 0.25 , \Omega ]

So, the resistance of the circuit is 0.25 ohms.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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