If a current of #8 A# passing through a circuit generates #104 W# of power, what is the resistance of the circuit?
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Using the formula ( P = I^2R ), where ( P ) is power, ( I ) is current, and ( R ) is resistance, we can rearrange it to solve for resistance:
[ R = \frac{P}{I^2} = \frac{104}{8^2} = \frac{104}{64} = 1.625 , \Omega ]
Therefore, the resistance of the circuit is 1.625 ohms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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