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If a current of #6 A# passing through a circuit generates #42 W# of power, what is the resistance of the circuit?

Answer 1

Nora Arzate

#R=7/6 ohm#

#P=I^2*R# #42=6^2*R# #42=36*R# #R=42/36# #R=7/6 ohm#

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Answer 2

Olivia Askew

Using the formula for power ( P = I^2R ), where ( P ) is power in watts, ( I ) is current in amperes, and ( R ) is resistance in ohms, we can rearrange the formula to solve for resistance:

( R = \frac{P}{I^2} )

Plugging in the given values:

( R = \frac{42, \text{W}}{(6, \text{A})^2} = \frac{42, \text{W}}{36, \text{A}^2} )

( R = 1.17, \Omega )

So, the resistance of the circuit is approximately ( 1.17, \Omega ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.