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If a current of #4 A# passing through a circuit generates #64 W# of power, what is the resistance of the circuit?

Answer 1

Julia Aguilar

The resistance is #=4Omega#

The current is #I=4A#

The power is #P=64W#

The power is

#P=UI#

and Ohm's Law is

#U=RI#

Therefore,

#P=UI=R*I*I=RI^2#

#R=P/I^2=64/4^2=4Omega#

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Answer 2

Olivia Askew

The resistance of the circuit can be calculated using the formula for electrical power: ( P = I^2 \times R ), where ( P ) is the power in watts, ( I ) is the current in amperes, and ( R ) is the resistance in ohms. Rearranging the formula to solve for resistance, we have: ( R = \frac{P}{I^2} ). Substituting the given values ( P = 64 ) W and ( I = 4 ) A into the formula, we get: ( R = \frac{64}{4^2} = \frac{64}{16} = 4 ) ohms. Therefore, the resistance of the circuit is 4 ohms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.