If a current of #3 A# passing through a circuit generates #35 W# of power, what is the resistance of the circuit?
Current squared by Resistance gives power.
R = 35/9 = 3.88 ohms since 3 x 3 x R = 35.
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The resistance of the circuit is 11.67 ohms.
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To find the resistance of the circuit, we can use the formula for power, which relates power (P), current (I), and resistance (R):
[ P = I^2 \times R ]
Given that the current (I) is 3 A and the power (P) is 35 W, we can rearrange the formula to solve for resistance (R):
[ R = \frac{P}{I^2} ]
[ R = \frac{35 , \text{W}}{(3 , \text{A})^2} ]
[ R = \frac{35 , \text{W}}{9 , \text{A}^2} ]
[ R = 3.89 , \Omega ]
So, the resistance of the circuit is approximately 3.89 ohms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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