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If a current of #2 A# passing through a circuit generates #49 W# of power, what is the resistance of the circuit?

Answer 1

Charles Aeschliman

#12.25 Omega#

In an electric circuit, #P=I^2R#.

#therefore R=P/I^2#

#=49/2^2#

#=12.25 Omega#

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Answer 2

Lily Adams

Using the formula for power ( P = I^2 \times R ), where ( P ) is power in watts, ( I ) is current in amperes, and ( R ) is resistance in ohms, we can rearrange to solve for resistance:

[ R = \frac{P}{I^2} ]

Substituting the given values:

[ R = \frac{49, \text{W}}{(2, \text{A})^2} ]

[ R = \frac{49, \text{W}}{4, \text{A}^2} ]

[ R = 12.25, \Omega ]

Therefore, the resistance of the circuit is ( 12.25 , \Omega ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.