If a current of #1 A# passing through a circuit generates #2 W# of power, what is the resistance of the circuit?

Answer 1

#2# ohms

For #R = # resistance (in Ohms) and #I= # current (in Amperes) and #P = # power (in Watts)
#P=RxxI^2 rarr R=P/(I^2)#
Given #color(white)("XXX")P=2W# and #color(white)("XXX")I=1A#
#R=2/1^2# Ohms #=2 # Ohms
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Answer 2

To find the resistance of the circuit, we can use the formula for power (P) in terms of current (I) and resistance (R), which is:

[ P = I^2 \times R ]

Given that the current (I) is 1 A and the power (P) is 2 W, we can rearrange the formula to solve for resistance (R):

[ R = \frac{P}{I^2} ]

Substituting the given values:

[ R = \frac{2 , \text{W}}{(1 , \text{A})^2} ]

[ R = 2 , \Omega ]

So, the resistance of the circuit is 2 ohms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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