If a circle has center (0,0) and a point on the circle (-2,-4) write the equation of the circle.?

Answer 1

#x^2+y^2 = 20#

Every point on a circle has the same distance from the center. This distance is the radius #r# of the circle.
So, if #(-2,-4)# is a point on the circle, it means that the radius of the circle is the distance between #(0,0)#, the center, and #(-2,-4)#.
To compute the distance between two points #(x_1y_1)# and #(x_2,y_2)#, the formula is
#d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}#
In this case, #(x_1y_1) = (0,0)# and #(x_2,y_2)=(-2,-4)#. So, their distance is
#d = \sqrt{(0-(-2))^2+(0-(-4))^2} = sqrt(4+16)=sqrt(20)#
Now we know the center #(0,0)# and the radius #sqrt(20)# of the circle. When you have this information, you can write the equation as
#(x-x_0)^2+(y-y_0)^2 = r^2#
where #(x_0,y_0)# is the center and #r# is the radius. So, in this case, the equation is
#(x-0)^2+(y-0)^2 = (sqrt(20))^2#

which can be rewritten as

#x^2+y^2 = 20#
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Answer 2

# x^2+ y^2 =20 #

The general equation of a circle of radius #r# centred on #(a,b)# is:
# (x-a)^2+ (y-b)^2 =r^2 #

Thus a circle centered on the origin will have an equation of the form:

# x^2+ y^2 =r^2 #
Knowing that #(-2,4)# lies on the circle, we have:
# (-2)^2+ (4)^2 =r^2 #
# :. r^2 = 4 + 16 = 20#

Thus the equation is

# x^2+ y^2 =20 #
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Answer 3

The equation of a circle with center (h, k) and radius r is given by the formula: (x - h)^2 + (y - k)^2 = r^2. Given that the center of the circle is (0, 0) and a point on the circle is (-2, -4), we can use these values to find the radius. The distance between the center (0, 0) and the point (-2, -4) can be found using the distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2). Substituting the given values, we get: d = √((-2 - 0)^2 + (-4 - 0)^2) = √(4 + 16) = √20. Since the distance from the center to any point on the circle is the radius, the radius of the circle is √20. Now, we can plug the center and the radius into the equation of the circle: (x - 0)^2 + (y - 0)^2 = (√20)^2. Simplifying, we get: x^2 + y^2 = 20. Therefore, the equation of the circle is x^2 + y^2 = 20.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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