If a circle has center (0,0) and a point on the circle (-2,-4) write the equation of the circle.?
which can be rewritten as
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# x^2+ y^2 =20 #
Thus a circle centered on the origin will have an equation of the form:
Thus the equation is
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The equation of a circle with center (h, k) and radius r is given by the formula: (x - h)^2 + (y - k)^2 = r^2. Given that the center of the circle is (0, 0) and a point on the circle is (-2, -4), we can use these values to find the radius. The distance between the center (0, 0) and the point (-2, -4) can be found using the distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2). Substituting the given values, we get: d = √((-2 - 0)^2 + (-4 - 0)^2) = √(4 + 16) = √20. Since the distance from the center to any point on the circle is the radius, the radius of the circle is √20. Now, we can plug the center and the radius into the equation of the circle: (x - 0)^2 + (y - 0)^2 = (√20)^2. Simplifying, we get: x^2 + y^2 = 20. Therefore, the equation of the circle is x^2 + y^2 = 20.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- A triangle has vertices A, B, and C. Vertex A has an angle of #pi/12 #, vertex B has an angle of #pi/6 #, and the triangle's area is #4 #. What is the area of the triangle's incircle?
- How do you graph #(x+1)^2+(y+2)^2=9#?
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