# If a ball is thrown vertically upward from the ground with an initial velocity of 56 feet per second, for how long will the ball be going upward?

This is an uniformed accelerated motion with

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To find the time the ball will be going upward, you can use the equation for vertical motion:

[ v_f = v_i - gt ]

Where: ( v_f ) = final velocity (when the ball reaches its peak, its final velocity is 0) ( v_i ) = initial velocity (given as 56 feet per second) ( g ) = acceleration due to gravity (approximately -32 feet per second squared, negative because it acts downward) ( t ) = time

Rearranging the equation to solve for ( t ):

[ t = \frac{{v_f - v_i}}{{-g}} ]

Plug in the values:

[ t = \frac{{0 - 56}}{{-32}} ]

[ t = \frac{{-56}}{{-32}} ]

[ t = 1.75 \text{ seconds} ]

So, the ball will be going upward for 1.75 seconds.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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