# If a 60 W light bulb is plugged into a standard 120 V source, how much current flows through the bulb?

Power= voltage x current

Here power is 60 watts. voltage is 120 so voltage x 0.5 amperes will make the power 60 watts. current= 0.5 amperes.

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To find the current flowing through the bulb, you can use Ohm's Law, which states:

Current (I) = Power (P) / Voltage (V)

Given that the power (P) of the light bulb is 60 W and the voltage (V) of the source is 120 V, you can plug these values into the formula:

Current (I) = 60 W / 120 V

Now, divide the power by the voltage:

I = 0.5 A

Therefore, 0.5 amperes (A) of current flows through the bulb.

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To calculate the current flowing through the 60 W light bulb plugged into a standard 120 V source, you can use Ohm's Law, which states that current (I) is equal to power (P) divided by voltage (V). The formula is:

I = P / V

Substitute the given values into the formula:

P = 60 W V = 120 V

I = 60 W / 120 V I = 0.5 A

Therefore, the current flowing through the bulb is 0.5 Amperes.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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