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If a #5 kg# object is being constantly accelerated from #0m/s# to #12 m/s# over # 16s#, how much power is being applied at #t= 1 s#?

Answer 1

William Audy

45 J/s.

see this..

power = work / time

power = ( force * distance travelled ) / time

power = ( (mass * acceleration) * distance travelled) / time

power = ( 5 kg * #12 m s^-1# / 16 s) * (16 s * 12 m/s) / 16 s

power = ( 3.75 ) * ( 192 ) / 16

power = 720 / 16

power = 45 J/s or 45 W

If object accelerates constantly than, the answer shows that 45 J ( Joule ) of energy is applied every second.

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Answer 2

Elena Albarran

To calculate power, use the formula: Power = Force × Velocity. First, find acceleration using the kinematic equation: (v = u + at). Then, use Newton's second law to find force: (F = ma). Finally, calculate power with (P = Fv). At (t = 1) s, the power applied is (30 \ \text{W}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.